类型:树
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- 二叉树的层序遍历 💛
https://leetcode-cn.com/problems/binary-tree-level-order-traversal/
❓ 给你一个二叉树,返回其层序遍历结果(二维数组)。
示例:
二叉树:[3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 结果: [ [3], [9,20], [15,7] ]💡 BFS
class Solution: def levelOrder(self, root: TreeNode) -> List[List[int]]: if not root: return [] ans = [] queue = [root] while queue: newQueue = [] row = [] for node in queue: row.append(node.val) if node.left: newQueue.append(node.left) if node.right: newQueue.append(node.right) ans.append(row) queue = newQueue return ans时间复杂度:O(n),空间复杂度:O(n)