类型:树
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- 翻转二叉树 💚
https://leetcode-cn.com/problems/invert-binary-tree/
❓ 翻转一个二叉树。
💡 递归
递归后序处理。
class Solution: def invertTree(self, root: TreeNode) -> TreeNode: if not root: return root left = self.invertTree(root.left) right = self.invertTree(root.right) root.left, root.right = right, left return root时间复杂度:O(n),空间复杂度:O(n)